What is the smallest number such that the sum of first three consecutive multiples of the number is 162?
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Answered by
0
Answer:
Let the number be x
Its multiples= x, 2x, 3x
According to question,
x+2x+3x=162
6x=162
x=162/6
x=27
Therefore the smallest number is 27
Answered by
0
Answer:27
Step-by-step explanation:x+2x+3x=162
6x=162
x=162/6
x=27
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