Question

What is the smallest number that divides by 35,56 and o1 leaves reminders of 7 in each case

Answer 1

Correct Question : What is the smallest number that divides by 35,56 and 91 and leaves reminders of 7 in each case?

Solution : Take the L.C.M of 35, 56 and 91

35 = 5 × 7

56 = 8 × 7

91 = 13 × 7

L.C.M = 5 × 8 × 13 × 7

= 3640

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Since number leave 7 remainder by dividing by each of these numbers,

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Number = 3640 + 7

= 3647