Question

What is the smallest number that leaves a remainder of 2 when divided by 3, 4, 5, and 6?

Answer 1

first find the LCM of 3, 4, 5 and 6

LCM = 60

Then add the remainder +2

Hence the answer is 62.

Answer 2

Given:

Remainder=2

The number is divided by 3, 4, 5, 6.

To find:

The smallest number is divisible by 3, 4, 5, 6 and leaves the remainder 2

Solution:

The required number is 62.

Let the required smallest number be X.

We are aware that the required number is to be divided by 5, 6, 4, 3.

The number leaves a remainder=2 on dividing by the aforementioned numbers.

So, we will calculate the LCM of 6, 5, 4, 3 to get the number.

The lowest multiple that is common between 6, 5, 4, 3=60

We divide X by 60 and get 2 as the remainder.

So, X has to be 2 more than the LCM.

X=60+2

X=62

Therefore, the required number is 62.