Question

What is the smallest number that must be added to 107 to make a number that is exactly divisible by 7?

Answer 1

Answer:

5 is the answer

Step-by-step explanation:

The Answer is 5.

107/7= 15 with remainder 2

But in the question, it has asked us about the number to be added to make it divisible by 7, that term is 112

So 112-107=5

The Answer is 5.

Answer 2

✨✨ Ello ✨✨

Here is the solution :-

Given number = 107 .

Number to be divided by = 7

Division = (refer to the attachment)

Now , in division 2 is left as remainder .

We will have to make it as 7 anyway and there is only 1 solution to do that , that is , to add it to 5 . we are going to add 5 not only to 2 but the whole number .

=> 107 + 5 = 112

Now , 112 is completely divisible by 7 .

so , 5 must be added to it.

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