Question

what is the smallest number that should be divided by 100to get a perfetc cube​

Answer 1

Answer

Correct option is

A

10

Prime factorising 100, we get,

100=2×2×5×5

         =2  

2

×5  

2

.

We know, a perfect cube has multiples of 3 as powers of prime factors.

Here, number of 2's is 2 and number of 5's is 2.

So we need to multiply another 2 and 5 in the factorization to make 100 a perfect cube.

Hence, the smallest number by which 100 must be multiplied to obtain a perfect cube is 2×5=10.

Answer 2

100 = 2*2*5*5

so, to be a perfect cube a number needs to be in a triplet , but here both the numbers are in pair

so, 100 = 2*2*5*5*1*1*1

here 1 is only in a triplet

(2*2*5*5) is the smallest number that should be divided to get a perfect cube

or, 100 should be divided

and the perfect cube is 1

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