Question

What is the smallest number that, when divided by
18
,
54
and
68
, leaves a remainder of
8
in each case?

Answer 1

Answer:

Required number is 1844

Step-by-step explanation:

Let the required number be x.

And the number leaves remainder 8,  

so number will be = (x − 8)

(x − 8) is the lest common multiple of 18, 54 and 68.

Now, we find LCM of 18, 54 and 68.

for LCM please refer the attachment

LCM =2×2×3×3×3×17= 1836

Therefore required number,

(x−8) = 1836

⇒ x = 1836  + 8

   x = 1844