Math, asked by njhambh3430, 7 months ago

What is the smallest number that when divided by 34,56&91 leaves remainder of 7 in each case

Answers

Answered by hritiksingh1

12

Answer:

The smallest number which when divided by 35, 56 and 91 = LCM(35,56,91)

35=5×7

56=2^3X7

91=7×13

LCM=2^3×5×7×13=3640

it leaves remainder 7 so add 7

3640+7=3647

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