Question

What is the smallest number that when divided by 35, 56, 91 leaves remainder of 7 in each case ? plzz show the method also !!

Answer 1

35 = 5×7
56 = 2×2×2×7
91= 7×13

LCM = 7×5×2×2×2×13 = 3640  the smallest number that when divide by 35 56 91 leaves a reminder 7 = 3640 + 7 =3647.

thank u

Answer 2

35 = 5×7

56 = 2×2×2×7

91= 7×13

LCM = 7×5×2×2×2×13 = 3640 the smallest number that when divide by 35 56 91 leaves a reminder 7 = 3640 + 7 =3647.

thank u