what is the smallest number that when divided by 35, 56 and 91 leaves remainder of 7 in each case.
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Step-by-step explanation:
since the question states for smallest no we have to find LCM
1st Subtract 7 from all 3 numbers
2nd You will get 28, 49, 84
3rd Hence find the LCM for all 3 numbers
4th you will get 252
That's the right answer hope it is helpful mark mine as the brainliest if u understand it.
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