Question

What is the smallest number that, when divided by 35, 56 and 91 leaves remainders of 7 in
each case​

Answer 1

Hello Mate

Answer :-3747

Step-by-step explanation:

here is your answer

LCM of 35, 56 &91 is 2 × 2 × 2 × 5 × 7 × 13

= 3640

then,3640 + 7 = 3647

$thanku$

#Be Brainly