Math, asked by vidhipatel129, 9 months ago

what is the smallest number that, when divided by 35 , 56 and 91 leaves remainders of 7 in each case ?​

Answers

Answered by yuvrajsingh94142
16

Answer:

The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.

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