What is the smallest number to be played in place of∆in the number 317∆2 so that the number formed is divisible by 9? Answer is5
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Answer:
Δ = 5
Step-by-step explanation:
Condition:-
⇒ Numbers are divisible by 9 if the sum of all the individual digits is evenly divisible by 9
Here,
the given number is 317Δ2,
Sum of all digits = 3 + 1+ 7 + Δ + 2
= 13 + Δ
If we put 5 in place of Δ then sum will be 18, which is divisible by 9
Hence Δ = 5
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