what is the smallest number when divided by either 6 or 5 leave a remainder of 2
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Take the lcm of 3,4,5,6.
3=3×1
4=2×2
5=5×1
6=2×3
LCM=2×2×3×5=60
2. Therefore 60 is the number that is completely divisible by these numbers. But we have to find the smallest number that leaves remainder 2.
Answer : 60+2=62
Step-by-step explanation:
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