Question

What is the smallest number which leaves remainder 3 when divided by any of the numbers 5,6 or 8 but leaves
no remainder when it is divided by 9?
A) 123
B) 603
C) 723
D) 243​

Answer 1

Answer: 243

Step-by-step explanation:

Just Divide those numbers using 9

When you divide 123 by 9 it leaves remainder 5

When you divide 723 by 9 it leaves remainder 3

When you divide 603 by 9 it leaves REMAINDER 0

when you divide 243 by 9 it leaves Remainder 0

AND WHEN YOU DIVIDE 603 By 2,5,8 it doesn't leave remainder 3

But by dividing 243 with those numbers it leaves remainder hence 243 is the answer :')

Well it's my first time answering So I might suck ig