What is the smallest number which leaves remainders 8 and 12 when divided by 28 and 32
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0 is the answer because if we divide we will get 0 only
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28-8=20
32-12=20
Thus,the whatever their L.C.M is, substract 20 from it.
L.C.M of 28 and 32 is-224
THE REQUIRED NUMBER IS=224-20
=204(ans)
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