Question

What is the smallest number which leaves remaindr 8 and 15 when divided by 28 and 32 respectively

Answer 1

Given that the smallest number when divided by 28 and 32 leaves remainder 8 and 12 respectively. 28 - 8 = 20 and 32 - 12 = 20 are divisible by the required numbers. Therefore the required number will be 20 less than the LCM of 28 and 32.calculation part I leaving onto you. calculate it and comment me the answer.