what is the smallest number which when divide by 24 36 and 54 gives a reminder of 5 each time
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Hi,
Here is your answer,
Find the smallest number that is divisible by all 3 of your numbers, then add 5 to it. So, first break the numbers into their prime factors:
24 = 2 * 2 * 2 * 3
36 = 2 * 2 * 3 * 3
54 = 2 * 3 * 3 * 3
So, the smallest number divisible by all 3 is 2 * 2 * 2 * 3 * 3 * 3 = 216. Add 5 to that to get 221.
I hope it helps you
plz mark as brainliest answer
Here is your answer,
Find the smallest number that is divisible by all 3 of your numbers, then add 5 to it. So, first break the numbers into their prime factors:
24 = 2 * 2 * 2 * 3
36 = 2 * 2 * 3 * 3
54 = 2 * 3 * 3 * 3
So, the smallest number divisible by all 3 is 2 * 2 * 2 * 3 * 3 * 3 = 216. Add 5 to that to get 221.
I hope it helps you
plz mark as brainliest answer
Jeevanurs:
ty but y we add 5 to 216
Answered by
0
This is the right answer
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