Question

what is the smallest number which when divided 24, 36, and 54 gives 5 as the remainder each time?

Answer 1

LCM of 24,36 and 54 is 216 
Therefore the number is 216+5=221
Hope it helps...

Answer 2

Answer:

Find the smallest number that is divisible by all 3 of your numbers, then add 5 to it. So, first break the numbers into their prime factors: 

24 = 2 * 2 * 2 * 3 

36 = 2 * 2 * 3 * 3 

54 = 2 * 3 * 3 * 3 

So, the smallest number divisible by all 3 is 2 * 2 * 2 * 3 * 3 * 3 = 216. Add 5 to that to get 221.