what is the smallest number which when divided by 12,18,and 27 gives a remainder of 5 each time
Answers
Answered by
5
Answer:
Prime factorizations first.
12 = 2 x 2 x 3
15 = 3 x 5
18 = 2 x 3 x 3
27 = 3 x 3 x 3
LCM = 2 x 2 x 3 x 3 x 3 x 5 = 540
Since all of the remainders are 4 less than the divisors, the number will be 540 - 4 = 536
Step-by-step explanation:
pls follow me and mark me as brainliest
Answered by
0
Answer:
12
Step-by-step explanation:
Similar questions