Question

what is the smallest number which when divided by 144,180 and 192 leaves remainder 3 in each case​

Answer 1

Step-by-step explanation:

A.T.Q,

The number leaves 3 as remainder.

So, 144 - 3  = 14

     180 - 3 = 177

     192 -  3 = 189

Now,

HCF of 141, 177 and 189 is 3.

And according to question It leaves remainder 3 in each case.

141 = 23 * 6 + 3

177 = 29 * 6 + 3

189 = 31 * 6 + 3

Thus, 6 is the number.

Answer 2

frnds it's correct above answer is not correct because isme hmse smallest pucha h largest nhi islia hm isme LCM nikalenege HCF nhi

hope guys it's helpful

and I m sure it's correct