What is the smallest number which when divided by 15 and 30 leaves no remainder?
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You are looking for the least common multiple of 15, 20, and 30. Perform prime factorization and include the minimum number of each prime from these numbers and multiply them together. You then have the lcm:
15 = 3 * 5
20 = 2 * 2 * 5
30 = 2 * 3 * 5
two 2’s by one 3 by one 5 = 2 * 2 * 3 * 5 = 60 That is the answer.
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