Math, asked by adwitavishal, 8 months ago

what is the smallest number which when divided by 18,24 and 36 leaves a remainder 3 in each case

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Answered by rottiou
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Given: Find the smallest number which when divided by 18,27, and 36 leaves a remainder 5 in each case. Result: The smallest number which when divided by 18,27, and 36 leaves a remainder 5 in each case is 113

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