Question

what is the smallest number which when divided by 20, 30 and 40 leaves a remainder 5​

Answer 1

Answer:

hlw mate

Explanation:

here's yr answer

120 is the least common multiple of 20, 30, and 40. So 125 leaves a multiple of 5 when divided by 20, 30, and 40.

hope it will help u

Answer 2

ANSWER:

• Required number = 125

GIVEN:

• 1st number = 20
• 2nd number = 30
• 3rd number = 40

TO FIND:

• A number which when divided by 20, 30 and 40 leaves a remainder 5 in each case.

SOLUTION:

Firstly , we have to find the LCM of 20; 30 and 40.

$20 = 5 \times 2 \times 2 \times 1 \\ 30 = 5 \times 3 \times 2 \times 1 \\ 40 = 5 \times 2 \times 2 \times 2$

Therefore, LCM:

$lcm = 5 \times 2 \times 2 \times 2 \times 3 \times 1 \\ lcm \: = 120$

20,30 and 40 divide 120 completely

so we have to add 5 to have 5 remainder in each case.

Required number = 120+5

= 125

NOTE:

• For this type of question we have to first find the LCM of the given number.
• Then we have to add the remainder which we want to bring.