What is the smallest number which when divided by 27, 36 and 5
7 gives a remainder of 5 in each case
Answers
Step-by-step explanation:
How did nationalist sentiment and education policy help in justifying military rule in japanSpecial economic zones policy was introduced in the year
Special economic zones policy was introduced in the yearHow did nationalist sentiment and education policy help in justifying military rule in japanSpecial economic zones policy was introduced in the year
Special economic zones policy was introduced in the year
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Step-by-step explanation:
Let's factorize,
24 = 2x2x2x3
36 = 2x2x3x3
54 = 2x3x3x3
The smallest number divisible by all 24, 36, 54 is:
LCM(24, 36, 54) = 216
Thus, to get 5 as remainder, we need to add 5 to 216.
(as 216 is the smallest number which gives remainder 0 when divided by 24 or 36 or 54)
216 + 5 = 221
For 12, 221 gives 18 as quotient and 5 as remainder
For 36, 221 gives 6 as quotient and 5 as remainder
For 54, 221 gives 4 as quotient and 5 as remainder
Hence, 221 is required number.
you can solve like this