Question

What is the smallest number which when divided by 35, 56, 91 leaves
remainder 3 in each case?

Answer 1

The numbers given are 35, 56, 91.

When the smallest number divided by the above numbers, they leave remainder of 7 in each case.

To Find:

The smallest number which when divided by the given numbers leaving remainder 7= ?

Solution:

Any smallest number dividing the numbers is nothing but the Least Common Multiple of all the numbers, which is LCM.  

Let us find the LCM of all the given numbers 35,56,91

So,LCM

Now the smallest number when divided by 35, 56, 91 leaves the remainder 7 in each case \bold{= 3640+7 = 3647}

3647 is the smallest number when divided by 35 , 56 , 91 leaves the remainder 7.

Answer 2

First you will take l.c.m ok then answer is ______ then less the no 3