What is the smallest number which when divided by 35,56,91 leaves a reminder 7 in each case
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Answered by
2
5,8,13 these are the anwsers.
sanasanajack:
will u pls explain how u get it
will you please explain how you get this ans
ooh sorry its saying that remainder should be 7.
The smallest number which when divided by 35, 56 and 91 = LCM of 35, 56 and 91
35 = 5 x 7
56 = 2 x 2 x 2 x 7
91 = 7 x 13
LCM = 7 x 5 x 2 x 2 x 2 x 13 = 3640
The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.
35 = 5 x 7
56 = 2 x 2 x 2 x 7
91 = 7 x 13
LCM = 7 x 5 x 2 x 2 x 2 x 13 = 3640
The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.
LCM = 7 x 5 x 2 x 2 x 2 x 13 = 3640. The smallest number which divides 35,56 and 91 is 3640. But we have a condition that it leaves a remainder of 7. So we add 7 to the LCM (3640+7=3647).
thank u so much Suraj Kumar
welcome
Answered by
0
Answer:
3647
Step-by-step explanation:
The smallest number which when divided by 35, 56 and 91 = LCM of 35, 56 and 91
35 = 5 x 7
56 = 2 x 2 x 2 x 7
91 = 7 x 13
LCM = 7 x 5 x 2 x 2 x 2 x 13 = 3640
The smallest number that when divided by 35, 56, 91 leaves a remainder 7 in each case = 3640 + 7 = 3647.
LCM = 7 x 5 x 2 x 2 x 2 x 13 = 3640. The smallest number which divides 35,56 and 91 is 3640. But we have a condition that it leaves a remainder of 7. So we add 7 to the LCM (3640+7=3647).
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