Math, asked by tejaswinimogal11, 6 months ago

What is the smallest number which when divided by 35, 56 and 91 leaves remainders of 7 in each case?

Answers

Answered by arunabhandari43349

4

Answer:

LCM 35,56,91 is 3640

which when divided by 35 56 and 91 leaves remainder of 7 in each case

3640+7=3647

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