Math, asked by Vanshikach1000, 1 year ago

What is the smallest number which when divided by 35, 56 and 91, leaves remainder 7 in each case?

Answers

Answered by bhuswati
5
LCM of 35,56,91 is 3185.

hence,

The smallest number is 3185 + 7 = 3192.
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