Question

What is the smallest number, which when divided by 7, 18, 56 and 36 leaves a remainder 0?

Answer 1

Answer:

504

Step-by-step explanation:

Required number = PCM of 7,18,56 and 36.

Pls refer to the attachment for the detailed solution.

Answer 2

The smallest number which is divided by 7, 18, 56 and 36 leaves a remainder 0 is 504.

Given:

The number will be divisible by 7, 18, 56 and 36.

To Find:

The smallest number which is divided by 7, 18, 56 and 36

Solution:

To get to the answer, you need to compute the lowest common multiple (LCM) of the given numbers.

To compute the LCM, we can proceed as follows -

7= 1×7

18= 2×3×3

56= 2×2×2×7

36= 2×2×3×3

Now, we multiply each prime factor the greatest number of times it occurs in either number​'s expansion.

LCM = 2×2×2×3×3×7= 504

Hence, the smallest number which is divided by 7, 18, 56 and 36 leaves a remainder 0 is 504.

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