Question

what is the smallest number which when divided by 7 and 5 leaves a remainder 4

Answer 1

First we will find the LCM of 7 and 5


7 = 7 × 1

5 = 5 × 1

LCM = 7 × 5

= 35


Least number = 35 + 4 = 39

Answer 2

To Find :

The smallest number which when divided by 7 and 5 leaves a remainder 4.

Solution :

We have to find the Least Common Multiple of 7 and 5 .

=> Least Common Multiple of 7 and 5 is = 7×5 = 35 .

Now , the smallest number which when divided leaves a reminder 4 is = 35+4 = 39 .

Verification =

39/7 =
$5 \times \frac{4}{7}$
The remainder is 4 .

39/5 =
$7 \times \frac{4}{5}$
The remainder is 4 .

#Be Brainly !!