Question

what is the smallest number which when increase by 6 become divisibel by 36, 63 and 108.​

Answer 1

Answer:

Step-by-step explanation:

Given numbers are 36, 63 and 108

LCM of 36, 63 and 108 is 756

given that the smallest number when increased by 6 is divisible  by the given numbers

Hence the smallest number is (756 –6) = 750

Answer 2

750 is the smallest number which when increased by 6 will be divisible by 36, 63 and 108

Step-by-step explanation:

• Factors /elements are the fantastic integers which could divide various evenly.
• Suppose we multiply numbers to get a product. The range this is elevated are the elements of the product. Each range is a component of itself.

So, the factors of the numbers in the question;

• 36 = 2x2x3x3
• 63 = 3x3x7
• 108 = 2x2x3x3x3

• LCM : In mathematics and quantity theory, the least not unusual place a couple of, lowest not unusualplace a couple of, or smallest not unusualplace a couple of of integers a and b, commonly denoted with the aid of using lcm, is the smallest advantageous integer this is divisible with the aid of using each a and b.
• or in simple words: LCM or Least Common Multiple is used to find the smallest common multiple of any two or more numbers.

LCM = 2x2x3x3x3x7 = 756

• To see smallest number which is increased by 6 :

subtract 6 in the LCM.

756–6 = 750

hence, 750 is the smallest number which when increased by 6 will be divisible by 36, 63 and 108

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Answer 3

Answer:

The smallest number which when increase by 6 become divisible by 36, 63 and 108 is 750.

Step-by-step explanation:

• In mathematics, LCM means Least common Factor. It is one of the smallest non-zero number which is common and they have two numbers which will become multiples of two numbers.
• The formula of LCM of two numbers is:

LCM of two numbers = products of two numbers/ HCF of two numbers

• There are different methods in LCM:

1) Prime Factorization Method

2) Division Method

Given that:

The numbers which are divisible is 36, 63 and 108 will increase by 6.

To find:

The smallest number =?

Solution:

Let us consider, the numbers 36, 63 and 108.

Now, we are going to take the LCM, we get,

2      36-63-108

2      18-63-56

3      9-63-27

3      3-21-9

3      1-7-3

7      1-7-1

       1-1-1

Therefore, we take the values that is divisibility and multiply,

Taking we get,

2 x 2 x 3 x 3 x 3 x 7 = 756

Now, we will consider the divisible value 6 and when we subtract the value, we get,

756-6 = 750.

Therefore, the smallest number is 750.

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