What is the smallest number which when increased by 3 is divisible by 16, 24, 30 and 32
Answers
Answer:
477
Step-by-step explanation:
First take out the L.C.M of 16,24,30,32=480
Now,the number we need is 3 less than 480
=477
Concept:
In mathematics, Least Common Multiple is referred to by its entire name, whereas Highest Common Factor is its complete name. The L.C.M. defines the least number that is exactly divisible by two or more numbers, whereas the H.C.F. describes the biggest factor existing between any given pair of two or more numbers. LCM is also known as the Least Common Multiple (LCM), and HCF is also known as the Greatest Common Factor (GCF).
We have two key techniques—the division method and the prime factorization approach—for determining H.C.F. and L.C.M.
Given:
16,24,30,32
Find:
What is the smallest number which when increased by 3 is divisible by 16, 24, 30 and 32
Solution:
First take out the L.C.M of 16,24,30,32=480
Now,the number we need is 3 less than 480
=477
Therefore, the smallest number which when increased by 3 is divisible by 16, 24, 30 and 32 is 477
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