What is the smallest number which when increased by 6 becomes divisible by 36,63 and 108
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Answer:
The smallest number which when increased by 6 becomes divisible by 36,63 and 108 = 750
Step-by-step explanation:
On factorizing 36 , 63 , 108, we will get:
36 = 2 × 2 × 3 × 3
63 = 7 × 3 × 3
108 = 2 × 2 × 3 × 3 × 3
Therefore Least Common Multiple of 36 , 63 , 108,
L.C.M = 756
The smallest number which when increased by 6 becomes divisible by 36,63 and 108 = 756 - 6 = 750
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