what is the smallest perfect square number which is completely divisible by 18,24,36, and 60
Answers
3600 is the smallest perfect square number which is completely divisible by 18,24,36, and 60
Step-by-step explanation:
First find the smallest number which is completely divisible by 18,24,36, and 60
to find that we need to find LCM of 18 , 24 , 36 & 60
18 = 2 * 3 * 3
24 = 2 * 2 * 2 * 3
36 = 2 * 2 * 3 * 3
60 = 2 * 2 * 3 * 5
LCM = 2 * 2 * 2 * 3 * 3 * 5
= 2² * 2 * 3² * 5
= ( 2 * 3)² * 2 * 5
To make it perfect square
we need to multiply it by 2 & 5
Then Number would be
6² * 2* 5 * 2 * 5
= 6² * 10²
= 60²
= 3600
3600 is the smallest perfect square number which is completely divisible by 18,24,36, and 60
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Answer:
Step-by-step explanation:
3600
3600 is the smallest perfect square number which is completely divisible by 18,24,36, and 60