What is the smallest positive integer meeting ALL the following conditions?
Dividing by 7 gives a remainder of 4.
Dividing by 8 gives a remainder of 5.
Dividing by 9 gives a remainder of 6.
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Answer:
⇒ Required Number −7= LCM of all the numbers. Therefore, the smallest number which when diminished by 7, is divisible 12, 16, 18, 21 and 28 is 1015. Thus, option (B) is the correct answer.
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Step-by-step explanation:
option B dividing by 8 gives a reminder of 5
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