What is the smallest positive integer n for which 324 is a factor of 6
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Step-by-step explanation:
324 = (2^2)*(3^4) = (6^2)*(9^1)
Any number to be completely divisible by 324 should have at least 6^2 and then should have a number divisible by 9. If it only in terms of powers of 6 then the number divisble by 9 would be 36 ( 6^2)
Therefore, (6*6*6*6)/(6^2)*(9^1) = 4.
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what do u want to ask
324 is a factor of 6
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