Question

what is the smallest possible integer value for n for which 63n is a multiple of 35?

Answer 1

Answer:

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Step-by-step explanation:

We first factorise 63 and 35,

63 = 3 * 3 * 7

35 = 5 * 7

Now find the HCF or GCF of the both, which is 7.

Divide 35 by 7,

35/7 = 5

n is equal to 5.

n=5

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