Question

what is the smallest square number which is divisible by each of the numbers 2,5,6​

Answer 1

First we have to find the LCM of 2,3,5,6 and 8

Then the LCM will be 120By taking the prime factorization of 120

We get,120=2×2×2×3×5 by taking these number in a pair of two the

number 2, 5 and 3 cannot be in pairSo we multiply the the whole number with 5 ,3 and 2.

So that we get each number in pair and by doing this we can get the perfect square root.

Now ,2×2×2×3×5×3×5×2=3600

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Answer 2

Answer:

3600

Step By Step Explanation:

Let First take L. C. M of 2,5,6

so we get 30= 2×3×5

So we can see that 2,3,5 are not in pairs so being then in pair we will multiply the the whole number with 5 ,6 and 2.

So that we get each number in pair and by doing this we can get the perfect square root.

So, 2×2×5×5×6×6=3600

So Final square root number that is exactly divisible by 2,5,6 is 3600