What is the smallest time t such that I = 4?
Answers
Answered by
0
Answer:
t
≈
0.0013
sec
o
n
d
s
Explanation:
4
=
8
sin
124
π
t
4
8
=
sin
124
π
t
sin
−
1
(
1
2
)
=
124
π
t
124
π
t
=
π
6
+
2
π
n
,
or
124
π
t
=
5
π
6
+
2
π
n
t
=
π
6
+
2
π
n
124
π
or
t
=
5
π
6
+
2
π
n
124
π
t
=
(
π
6
+
2
π
n
)
⋅
1
124
π
or
t
=
(
5
π
6
+
2
π
n
)
⋅
1
124
π
t
=
1
744
+
1
62
n
or
t
=
5
744
+
1
62
n
where
n
=
0
,
±
1
,
±
2
,
±
3
,
...
Since time is positive we are looking for the first positive answer. So pick n values and plug it to the two equations.
n
=
0
,
t
≈
0.0013
or
t
≈
.00672
Note that if we pick n = -1 then we get two negative answers and if we pick n = 1 then we get 0.0175 and 0.02285 which are bigger than the values for n = 0 so the smallest time t when I = 4 is about 0.0013 sec.
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