What is the smallest value of n greater than one such that square root of the sum of all natural numbers upto n is a positive integer
Answers
Answered by
0
please see the attachment
Attachments:
VedanshSomani:
Y did trial and error method but I need the process
let √n(n+1)/2=k. squareing both sides and cross multiply,we get n^2+n-k^2=0.there fire n=(-1+√1+8k^2)/2.lf n is least positive integer k should be 6. so n=(-1+17)
n=(-1+17)/2=8
see the correction please.
Couldn't understand the second comment. I will ask the question again then plz reply to it
Similar questions