Question

what is the smallest volume of water, in mL, required to completley dissolve 39 grams of KNO3 at 10 degrees C

Answer 1

Answer:

Explanation:

The solubility graph is a very useful tool because it tells you the amount of potassium nitrate that can be dissolved per

100 mL

of water in order to have a saturated solution of potassium nitrate at a given temperature.

In order to find the solubility of the salt at

60

∘

C

, start from the

60

∘

C

mark on the graph and move up until you intersect the curve. At the point of intersection, move left until you intersect the

y

axis and read off the value that you land on.

In this case, you can estimate that the solubility of potassium nitrate in water at

60

∘

C

is equal to about

solubility

≈

110 g / 100 mL water

−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−−

This tells you that a saturated solution of potassium nitrate will hold about

110 g

of dissolved salt, i.e. of dissociated salt, per

100 mL

of water at

60

∘

C

.