What is the smallest which when increased by 6becomes divisible by 36,63,108
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3
Answer:
750
Explanation:
The smallest number divisible by 36, 63 and 108 is the L.C.M
In calculating this, we have
36=2*2*3*3
63=7*3*3
108=2*2*3*3*3
L.C.M=2*2*3*3*3*7=756
The number increased by 6 to be 756 is 750.
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