English, asked by shahchitra6270, 1 year ago

What is the smallest which when increased by 6becomes divisible by 36,63,108

Answers

Answered by maxie2405
3

Answer:

750

Explanation:

The smallest number divisible by 36, 63 and 108 is the L.C.M

In calculating this, we have

36=2*2*3*3

63=7*3*3

108=2*2*3*3*3

L.C.M=2*2*3*3*3*7=756

The number increased by 6 to be 756 is 750.

Similar questions