What is the smallest whole number which is divisible by 10/3, 15 and 35/2
without remainder?
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Step-by-step explanation:
What is the smallest number that is divisible by 15 and 35 leaves 2 as remainder in each case?
“Is divisible by” is not the same as “leaves 2 as a remainder.” I think you mean “What is the smallest positive integer that, when divided by 15 or 35 leaves 2 as remainder.”
So we are saying our number, n is expressible as
n=15x+2 and
n=35y+2
As a consequence, we can say
15x+2=35y+2
15x=35y
3x=7y
So if we set x=7 and y = 3, we’ll get an answer of
n=15∗7+2=107
And checking our result: 107/15 = 7 rem 2; 107/35 = 3 rem 2.
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