Question

What is the solublity of sodium nitrate at 20oC, if 17.6gm of sodium forms saturated solution in 20gm of water?​

Answer 1

Answer:

Explanation:

Solution,

Here

Solubility = 70.5

Weight of saturated solution = 20 g

Weight of solute = X (let)

Weight of solvent = (20 – X) g

Now

Solubility =WeightofsoluteingmWeightofsolventingm * 100

                                                             

Or, 70.5 =  X20−X* 100

 

Or, 70.5 (20 – X) = 100X

Or, 1410 – 70.5X = 100X

Or, 170.5X = 1410

\ X = 1410 /170.5 = 8.2 g

Then, 20 – X = 20 – 8.2 = 11.7 g

Therefore, the amount of sodium carbonate in the solution was 8.2 g

The solubility of a substance changes along with the temperature so in order to get required solubility the temperature should be mentioned correctly.