What is the solution for (a+2b+3c)³
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take a+2b be X
now
(X+3c)^3=X3+27c^3+9x^2c+27c^2x
now
since x=a+2b
x^3=a^3+8b^3+6a^2*b+12b^2a
x^2=a2+4b^2+4ab
so using above equation we write
(a+2b+3c)^3=c^3+a^3+8b^3+6a^2b+12b^2a+ca^2+4cb^2+4abc+27c^2a+54c^2b
ok is the expansion .......
now
(X+3c)^3=X3+27c^3+9x^2c+27c^2x
now
since x=a+2b
x^3=a^3+8b^3+6a^2*b+12b^2a
x^2=a2+4b^2+4ab
so using above equation we write
(a+2b+3c)^3=c^3+a^3+8b^3+6a^2b+12b^2a+ca^2+4cb^2+4abc+27c^2a+54c^2b
ok is the expansion .......
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