what is the solution of √2x-√5y=0 and 2√3x-7y=0
Answers
Answer:
Change 2x+5y +1=0 to 2x+5y = - 1
Now:
3x+7y=1
2x+5y = - 1
Multiply first equation by - 2, term by term
Multiply second equation by 3, term by term
So, - 6x - 14y = - 2
and 6x + 15y = - 3
Now when we add the equations together, term by term, the x-terms will “drop out”.
y = - 5
Replace back in to either original equation to find x. Then take (x, y) and check in the (original) equation that you didn’t use to find x.
Second equation: 2x+5(-5) = - 1
2x - 25 = - 1
2x = 24
x = 24/2 = 12.
Check (12, - 5) in First equation
3(12)+7(-5)=1 Work ONLY the left side
36 - 35
1 Left side = right side
(x, y) = (12, - 5) is the solution to the system.
Answer:
the value of x and y is zero
given:- equations √2x+3y=0 and √3y-√7y=0
to find :- solve the questions
Step-by-step explanation:
solution:- root 2 x + root 3 y is equal to zero...(1)
root 3 x minus root 7 y is equal to zero... (2)
multiple (1) by root 3 and (2) by root 2.
root 6 x + root 9 y is equal to zero.. (3)
root 6x.... root 16 y is equal to zero.... (4) subtracting (4) from (3)
root 9y+root 16 y is equal to zero
y is equal to zero
from (1)
root 2 x + root 3 (0)=0
root 2 x is equal to zero
x is equal to zero
x is equal to zero, y is equal to zero (answer)
hope this will help you
have a great day
Answer:
the value of x and y is zero
given:- equations √2x+3y=0 and √3y-√7y=0
to find :- solve the questions
Step-by-step explanation:
solution:- root 2 x + root 3 y is equal to zero...(1)
root 3 x minus root 7 y is equal to zero... (2)
multiple (1) by root 3 and (2) by root 2.
root 6 x + root 9 y is equal to zero.. (3)
root 6x.... root 16 y is equal to zero.... (4) subtracting (4) from (3)
root 9y+root 16 y is equal to zero
y is equal to zero
from (1)
root 2 x + root 3 (0)=0
root 2 x is equal to zero
x is equal to zero
x is equal to zero, y is equal to zero (answer)
hope this will help you
have a great day