Question

What is the solution of log2x − 3125 = 3?

Answer 1

Am assuming we are dealing with common logarithm (That's logarithm to base 10)

log2x - 3125 = 3
log2x = 3+3125
log2x = 3128

log2x = log2 + logx = 3128
logx = 3128-log2
logx = 3127.7

x = 10^3127.7

Answer 2

Answer:

We have to calculate the value of x in log2x – 3125 = 3

We can solve this with the help of algebra and certain logarithmic formulas.

log2x - 3125 = 3

log2x = 3+3125

log2x = 3128

Using the expression: log(a.b) = log a + log b

log2x = log2 + logx = 3128

logx = 3128-log2

logx = 3127.7

$x=10^{3127.7}$ (Assume that the base is 10)