What is the solution of log4 16 - 2log4x=1?
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Answered by
1
Step-by-step explanation:
log 16 base 4 = log 4² base 4 = 2log4 base4 = 2
2logx base 4= log x² base4
so given question becomes
2- log x² base 4 =1
log x² base 4 = 2-1 =1
x² = 4¹ = 2²
x= 2
Answered by
0
log 4 base 16-2 log x base 4=1
2-log x² base 4 =1
log x²base 4 =1
x²=4
x=2
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