what is the solution of t^2-2t-40
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Step-by-step explanation:
t^2-2t-40 = 0
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Answer:
t^2-2 (t+20)=0
=t^2÷2-2(t+20)÷2=0
2 under t^2 will be shifted to the right hand side and 2 will be cut by 2 under (t+20)
t^2-t-20
factorizing 20
t^2-5t+4t-20
t (t-5)+4 (t -5)
(t-5)(t+4)
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