Question

what is the solution of
$\tan ^{ - 1} (2x) + \tan ^{ - 1}3x \: = \: \frac{\pi}{4}$
​

Answer 1

Answer:

SEE MY ATTACHMENT

Step-by-step explanation:

1) I use the formula

tan ^-1 (x) + tan ^-1 (y) = tan ^-1 x + y / 1- xy

2) put values

3) consider LHS = RHS

4) evaluate π/4 in terms of tan

tan π/4 = 1

π/4 = tan ^-1 ( 1 )

5) compare LHS and RHS

6) after comparing u will get value of ' x '

HOPE IT HELP U